According to Cahn-Ingold-Prelog sequence rule | vedclass

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Question

(A) According to the Cahn-Ingold-Prelog $(CIP)$ sequence rules,priority is assigned based on the atomic number of the atom directly attached to the ch

Vedclass · Accepted Answer

$-OH > -COOH > -CHO > -CH_2OH$

Vedclass · Answer

(A) According to the Cahn-Ingold-Prelog $(CIP)$ sequence rules,priority is assigned based on the atomic number of the atom directly attached to the chiral center. $1$. The atom with the higher atomic number gets higher priority. $2$. Comparing the atoms attached to the chiral center: $O$ (atomic number $8$) in $-OH$ has the highest priority. $3$. For the remaining groups ($-COOH$,$-CHO$,$-CH_2OH$),the atom attached is $C$ (atomic number $6$). $4$. We look at the next atoms: - In $-COOH$ ($C$ is bonded to $O, O, O$ via double bond equivalent),- In $-CHO$ ($C$ is bonded to $O, O, H$ via double bond equivalent),- In $-CH_2OH$ ($C$ is bonded to $O, H, H$). Comparing these,the order is $-COOH > -CHO > -CH_2OH$. Thus,the overall priority order is $-OH > -COOH > -CHO > -CH_2OH$.

According to Cahn-Ingold-Prelog sequence rules,the correct order of priority for the given groups is

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