According to Joule's law of heating,heat prod | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the formula for heat produced: $H = I^2Rt$.The relative error in $H$ is given by the propagation of errors formula:$\frac{\Delta H}{H} = 2\f

Vedclass · Accepted Answer

$ \pm 16\%$

Vedclass · Answer

(B) Given the formula for heat produced: $H = I^2Rt$.The relative error in $H$ is given by the propagation of errors formula:$\frac{\Delta H}{H} = 2\frac{\Delta I}{I} + \frac{\Delta R}{R} + \frac{\Delta t}{t}$.To find the percentage error,we multiply by $100$:$\frac{\Delta H}{H} 	imes 100 = \left( 2 	imes \frac{\Delta I}{I} 	imes 100 + \frac{\Delta R}{R} 	imes 100 + \frac{\Delta t}{t} 	imes 100 ight)$.Substituting the given percentage errors $(3\%, 4\%, 6\%)$:$\frac{\Delta H}{H} 	imes 100 = (2 	imes 3\% + 4\% + 6\%)$.Calculating the result:$\frac{\Delta H}{H} 	imes 100 = (6\% + 4\% + 6\%) = 16\%$.Thus,the error in the measurement of $H$ is $\pm 16\%$.

Day	Clock $1$	Clock $2$
Monday	$12:00:05$	$10:15:06$
Tuesday	$12:01:15$	$10:14:59$
Wednesday	$11:59:08$	$10:15:18$
Thursday	$12:01:50$	$10:15:07$
Friday	$11:59:15$	$10:14:53$
Saturday	$12:01:30$	$10:15:24$
Sunday	$12:01:19$	$10:15:11$

According to Joule's law of heating,heat produced $H = I^2Rt$,where $I$ is current,$R$ is resistance,and $t$ is time. If the errors in the measurement of $I, R$,and $t$ are $3\%, 4\%$,and $6\%$ respectively,then the error in the measurement of $H$ is:

Similar Questions

Consider a series of measurements of the length of a box in an experiment. The readings are $2.4 \ m, 2.5 \ m, 2.6 \ m, 2.8 \ m, 3.0 \ m$. What would be the relative error?

The unit of percentage error is

The mass of an empty beaker is $(10.1 \pm 0.1) \, g$. When it is completely filled with a liquid,its mass becomes $(17.3 \pm 0.1) \, g$. What is the best value for the mass of the liquid within the possible limits of accuracy?

The maximum percentage error in the measurement of the density of a wire is: [Given: mass of wire $= (0.60 \pm 0.003) \ g$,radius of wire $= (0.50 \pm 0.01) \ cm$,length of wire $= (10.00 \pm 0.05) \ cm$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module