According to the nuclear reaction $_4Be + _2He^4 \to _6C^{12} + _0n^1$,what is the mass number of the $Be$ atom?

An element ${ }_{x} A^{y}$ emits $5$ $\alpha$ and $4$ $\beta$ particles to give ${ }_{82} B^{207}$. The number of protons and neutrons in $A$ are respectively

For the nuclear reaction,$_{12}^{24}Mg + _{1}^{2}D \to _{2}^{4}He + ?$,the missing nuclide is

What is $X$ in the following reaction?
${}_{12}Mg^{26} + {}_{1}H^{2} \longrightarrow {}_{12}Mg^{27} + X$

Artificial transmutation was discovered by

The nuclear reaction $_{29}^{63}Cu + _{2}^{4}He \to _{17}^{37}Cl + 14_{1}^{1}H + 16_{0}^{1}n$ is referred to as