Acetaldehyde can be converted into C(CH_2OH)_ | vedclass

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(C) The reaction of acetaldehyde $(CH_3CHO)$ with excess formaldehyde $(HCHO)$ in the presence of a base like $KOH$ proceeds via a series of aldol add

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excess of $HCHO$ and $KOH$

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(C) The reaction of acetaldehyde $(CH_3CHO)$ with excess formaldehyde $(HCHO)$ in the presence of a base like $KOH$ proceeds via a series of aldol additions followed by a crossed Cannizzaro reaction.$1$. $CH_3CHO + 3HCHO \xrightarrow{OH^-} (HOCH_2)_3C-CHO$$2$. $(HOCH_2)_3C-CHO + HCHO + OH^- \rightarrow (HOCH_2)_3C-CH_2OH + HCOO^-$The final product is pentaerythritol,$C(CH_2OH)_4$.

Acetaldehyde can be converted into $C(CH_2OH)_4$ (pentaerythritol) by which reagent?

Similar Questions

Which of the following represents the correct order of reactivity towards nucleophilic addition reactions?

Which of the following compounds does not give an Aldol condensation reaction?

Identify the compounds $A$ and $B$ involved in the formation of the given aldol product: $A + B \xrightarrow{OH^-} CH_3-CH_2-CH(OH)-CH(CH_3)-CHO$

$CH_3CHO$ reacts with aqueous $NaOH$ solution to form

Consider the following reaction sequence:
$B \xleftarrow{NaBH_4} CH_2=CH-CHO \xrightarrow{H_2/Pt} A$
Identify $A$ and $B$.

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