Acetylene reacts with a $42\% H_2SO_4$ solution containing $1\% HgSO_4$ to give

  • A
    $C_2H_5HSO_4$
  • B
    $CH_2=CH_2$
  • C
    $CH_3CHO$
  • D
    $HCHO$

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Consider the following sequence,where $A$ can be:
$A$ $(C_{3}H_{6}Cl_{2})$ $\xrightarrow[2. \, H^{+} \, (mild)]{1. \, \text{alcoholic } KOH / \Delta, \text{ followed by } NaNH_{2} / \Delta}$ $B$ $\xrightarrow[H_{2}O_{2} / OH^{-}]{B_{2}H_{6}}$ $C$
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