Action of hydrogen chloride on CH_3-C(CH_3)=C | vedclass

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(B) The addition of $HCl$ to $2$-methylpropene follows Markovnikov's rule,where the $Cl^-$ attaches to the more substituted carbon atom.$CH_3-C(CH_3)=

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$CH_3-CCl(CH_3)-CH_3$ and $CH_3-CHCl_2$

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(B) The addition of $HCl$ to $2$-methylpropene follows Markovnikov's rule,where the $Cl^-$ attaches to the more substituted carbon atom.$CH_3-C(CH_3)=CH_2 + HCl \rightarrow CH_3-CCl(CH_3)-CH_3$The addition of $HCl$ to ethyne follows Markovnikov's rule in the second step,leading to the formation of a geminal dihalide.$CH \equiv CH + HCl$ $\rightarrow CH_2=CHCl$ $\xrightarrow{HCl} CH_3-CHCl_2$Thus,the products are $CH_3-CCl(CH_3)-CH_3$ and $CH_3-CHCl_2$.

List-$I$	List-$II$
$A.$ Butane $\to$ Isobutane	$(a).$ Cracking
$B.$ Butane $\to$ Lower hydrocarbons	$(b).$ Isomerisation
$C.$ $n-$Heptane $\to$ Toluene	$(c).$ Reed reaction
$D.$ Propane $\to CH_3CH_2CH_2SO_2Cl$	$(d).$ Aromatization

Action of hydrogen chloride on $CH_3-C(CH_3)=CH_2$ and on $CH \equiv CH$ will predominantly give the compounds,respectively:

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