The action of water in the presence of sulphu | vedclass

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(A) The hydration of alkenes in the presence of $H_2SO_4$ follows the Markownikoff rule,where the hydroxyl group $(-OH)$ attaches to the more substitu

Vedclass · Accepted Answer

$(i)$ $CH_3-CH_2-C(OH)(CH_3)_2$(ii) $CH_3-CH(OH)-CH_3$

Vedclass · Answer

(A) The hydration of alkenes in the presence of $H_2SO_4$ follows the Markownikoff rule,where the hydroxyl group $(-OH)$ attaches to the more substituted carbon atom.$(i)$ For $CH_3-CH=C(CH_3)_2$ ($2$-methylbut$-2-$ene):The double bond is between $C2$ and $C3$. The $C3$ atom is more substituted than $C2$. Thus,the $-OH$ group attaches to $C3$,yielding $CH_3-CH_2-C(OH)(CH_3)_2$ ($2$-methylbutan$-2-$ol).(ii) For $CH_3-CH=CH_2$ (propene):The double bond is between $C1$ and $C2$. The $C2$ atom is more substituted than $C1$. Thus,the $-OH$ group attaches to $C2$,yielding $CH_3-CH(OH)-CH_3$ (propan$-2-$ol).Therefore,the correct products are:$(i)$ $CH_3-CH_2-C(OH)(CH_3)_2$(ii) $CH_3-CH(OH)-CH_3$

The action of water in the presence of sulphuric acid on the following alkenes gives:
$(i)$ $CH_3-CH=C(CH_3)_2$
(ii) $CH_3-CH=CH_2$

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The action of water in the presence of sulphuric acid on the following alkenes gives:$(i)$ $CH_3-CH=C(CH_3)_2$(ii) $CH_3-CH=CH_2$