Addition of excess of AgNO_3 to an aqueous so | vedclass

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(A) The reaction of $1$ mole of $PdCl_2 \cdot 4 NH_3$ with excess $AgNO_3$ produces $2$ moles of $AgCl$ precipitate,which indicates that $2$ chloride

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$1:2$ electrolyte

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(A) The reaction of $1$ mole of $PdCl_2 \cdot 4 NH_3$ with excess $AgNO_3$ produces $2$ moles of $AgCl$ precipitate,which indicates that $2$ chloride ions $(Cl^-)$ are present outside the coordination sphere.Thus,the complex can be formulated as $[Pd(NH_3)_4]Cl_2$.In aqueous solution,it dissociates as: $[Pd(NH_3)_4]Cl_2 \rightarrow [Pd(NH_3)_4]^{2+} + 2Cl^-$.This produces $1$ cation and $2$ anions,making it a $1:2$ electrolyte.

Addition of excess of $AgNO_3$ to an aqueous solution of $1$ mole of $PdCl_2 \cdot 4 NH_3$ gives $2$ moles of $AgCl$. The conductivity of this solution corresponds to

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