(A) The sequence of reactions is as follows:$1$. $2AgNO_{3} + Na_{2}S_{2}O_{3} \rightarrow Ag_{2}S_{2}O_{3} \downarrow (X) + 2NaNO_{3}$$2$. $Ag_{2}S_{

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$Ag_{2}S_{2}O_{3}$, $Na_{3}[Ag(S_{2}O_{3})_{2}]$, $Ag_{2}S$

(A) The sequence of reactions is as follows:$1$. $2AgNO_{3} + Na_{2}S_{2}O_{3} \rightarrow Ag_{2}S_{2}O_{3} \downarrow (X) + 2NaNO_{3}$$2$. $Ag_{2}S_{2}O_{3} + 3Na_{2}S_{2}O_{3} \rightarrow 2Na_{3}[Ag(S_{2}O_{3})_{2}] (Y)$$3$. $2Na_{3}[Ag(S_{2}O_{3})_{2}] + H_{2}O \xrightarrow{\Delta} Ag_{2}S (Z) + Na_{2}SO_{4} + 2Na_{2}S_{2}O_{3} + H_{2}SO_{4}$Thus, $X = Ag_{2}S_{2}O_{3}$, $Y = Na_{3}[Ag(S_{2}O_{3})_{2}]$, and $Z = Ag_{2}S$.

Class 12 Chemistry Principles Related to Practical Chemistry Wet Test for Basic Radical

Easy

Addition of sodium thiosulphate solution to a solution of silver nitrate gives $X$ as a white precipitate, which is insoluble in water but soluble in excess thiosulphate solution to give $Y$. On boiling in water, $Y$ gives $Z$. $X$, $Y$, and $Z$ respectively are:

WBJEE 2015 All WBJEE

A
$Ag_{2}S_{2}O_{3}$, $Na_{3}[Ag(S_{2}O_{3})_{2}]$, $Ag_{2}S$
B
$Ag_{2}SO_{4}$, $Na[Ag(S_{2}O_{3})_{2}]$, $Ag_{2}S_{2}$
C
$Ag_{2}S_{2}O_{3}$, $Na_{5}[Ag(S_{2}O_{3})_{3}]$, $AgS$
D
$Ag_{2}SO_{3}$, $Na_{3}[Ag(S_{2}O_{3})_{2}]$, $Ag_{2}O$

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Addition of sodium thiosulphate solution to a solution of silver nitrate gives $X$ as a white precipitate, which is insoluble in water but soluble in excess thiosulphate solution to give $Y$. On boiling in water, $Y$ gives $Z$. $X$, $Y$, and $Z$ respectively are:

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Compound $A$ on borax bead test in reducing flame gives green colour bead. Compound $A$ on treatment with $H_2O_2$ followed by treatment with $Pb(OAc)_2$ gives yellow ppt. The metal ion in the compound $A$ is :

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