After filling the 4d orbitals,an electron wil | vedclass

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(C) According to the $(n + l)$ rule,electrons fill orbitals in increasing order of their $(n + l)$ values.For the $4d$ orbital,$n = 4$ and $l = 2$,so

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$5p$

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(C) According to the $(n + l)$ rule,electrons fill orbitals in increasing order of their $(n + l)$ values.For the $4d$ orbital,$n = 4$ and $l = 2$,so $(n + l) = 4 + 2 = 6$.For the $5p$ orbital,$n = 5$ and $l = 1$,so $(n + l) = 5 + 1 = 6$.When the $(n + l)$ values are equal,the orbital with the lower value of $n$ is filled first.Since $4 Therefore,after filling the $4d$ orbital,the next electron will enter the $5p$ orbital.

After filling the $4d$ orbitals,an electron will enter in:

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