Air contains 70% , N_2, , 20% , O_2 and 1% , | vedclass

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(A) According to Dalton's Law of Partial Pressures,the partial pressure of a gas is given by the product of its mole fraction and the total pressure.

Vedclass · Accepted Answer

$P_{N_2} = 0.70 \, bar, P_{O_2} = 0.20 \, bar, P_{CO_2} = 0.01 \, bar$

Vedclass · Answer

(A) According to Dalton's Law of Partial Pressures,the partial pressure of a gas is given by the product of its mole fraction and the total pressure. Since volume percentage is equal to mole fraction in a gaseous mixture,the mole fractions are: $x_{N_2} = 0.70, x_{O_2} = 0.20, x_{CO_2} = 0.01$. Given total pressure $P_{total} = 1 \, bar$. Partial pressure $P_i = x_i 	imes P_{total}$. $P_{N_2} = 0.70 	imes 1 \, bar = 0.70 \, bar$. $P_{O_2} = 0.20 	imes 1 \, bar = 0.20 \, bar$. $P_{CO_2} = 0.01 	imes 1 \, bar = 0.01 \, bar$.

Air contains $70\% \, N_2, \, 20\% \, O_2$ and $1\% \, CO_2$ by volume. If the total pressure of air is $1 \, bar$,find the partial pressure of $N_2, O_2$ and $CO_2$.

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