Alcoholic solution of KOH is used for | vedclass

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Question

(C) The correct answer is $(C)$.Alcoholic $KOH$ contains alkoxide ions $(RO^-)$,which act as strong bases.These ions abstract a proton from the $\beta

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Dehydrohalogenation

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(C) The correct answer is $(C)$.Alcoholic $KOH$ contains alkoxide ions $(RO^-)$,which act as strong bases.These ions abstract a proton from the $\beta$-carbon of an alkyl halide,leading to an elimination reaction known as dehydrohalogenation.The reaction is: $CH_3-CH_2-Br + KOH_{(alc)} \xrightarrow{\Delta} CH_2=CH_2 + KBr + H_2O$.Mechanism:$ROH + KOH 	o ROK + H_2O$$ROK 	o RO^- + K^+$$RO^- + H-CH_2(\beta)-CH_2(\alpha)-Br 	o ROH + CH_2=CH_2 + Br^-$

Alcoholic solution of $KOH$ is used for

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The following reaction is a/an:
$CH_3-CH_2-CH_2-Br \xrightarrow{KOH} CH_3-CH=CH_2 + KBr + H_2O$

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