Aldol condensation will not be observed in

$HCHO$ (more reactive towards oxidation) + $CH_3CHO \xrightarrow{Conc. NaOH}$ Find out the products of the reaction.

This conversion can be achieved by

$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{\text{Jones reagent}} X$,
Product $X$ is

Given below are two statements:
Statement $I$: $H_2N-CO-CH_2-CH_2-CO-CH_3$ under Clemmensen reduction conditions will give $HOOC-(CH_2)_3-CH_3$.
Statement $II$: $CH_3-CH(CH_3)-CH_2-CH(Cl)-CO-CH_3$ under Wolff-Kishner reduction conditions will give $CH_3-CH(CH_3)-CH_2-CH(Cl)-CH_2-CH_3$.
In the light of the above statements,choose the correct answer from the options given below:

Product $A$ is