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(B) The circuit consists of two identical groups of capacitors connected in series.Each group consists of three identical capacitors connected in para

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$400$

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(B) The circuit consists of two identical groups of capacitors connected in series.Each group consists of three identical capacitors connected in parallel.Since the capacitors in each group are in parallel,the voltage across each capacitor in a group is the same as the voltage across the group itself.Given that each capacitor can withstand a maximum of $200 \, V$,the maximum voltage that can be applied across each group is $200 \, V$.Let $V_1$ be the voltage across the first group and $V_2$ be the voltage across the second group.The total voltage applied between $A$ and $B$ is $V_{AB} = V_1 + V_2$.To maximize $V_{AB}$,we set $V_1 = 200 \, V$ and $V_2 = 200 \, V$.Therefore,$V_{AB, 	ext{max}} = 200 \, V + 200 \, V = 400 \, V$.

All the six capacitors shown in the circuit are identical. Each can withstand a maximum of $200 \, V$ between its terminals. The maximum voltage that can be applied safely between $A$ and $B$ is.....$V$

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