$A$ capillary tube of radius $r$ is initially just vertically completely immersed inside a liquid of angle of contact $0^{\circ}$. If the tube is slowly raised,then the relation between the radius of curvature of the meniscus inside the capillary tube and the displacement $(h)$ of the tube can be represented by:

Three liquids of densities $\rho_1, \rho_2$ and $\rho_3$ (with $\rho_1 > \rho_2 > \rho_3$),having the same value of surface tension $T$,rise to the same height in three identical capillaries. The angles of contact $\theta_1, \theta_2$ and $\theta_3$ obey:

How does an oil lamp produce light through a wick that is lit using a match?

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary of radius $\frac{r}{5}$ will be:

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary tube of radius $\frac{r}{3}$ will be:

The height of a liquid column raised in a capillary tube of a certain radius when dipped in liquid $A$ vertically is $5 \ cm$. If the tube is dipped in a similar manner in another liquid $B$ with surface tension and density double the values of liquid $A$,the height of the liquid column raised in liquid $B$ would be $........ \ m$.