Medium
Although carbon and hydrogen are better reducing agents,they are not used to reduce metallic oxides at high temperatures. Why?
(N/A) This is due to the formation of metal carbides and metal hydrides at high temperatures.
$CaO + 3C \xrightarrow{2273 \ K} CaC_2 + CO$
$Ca + H_2 \rightarrow CaH_2$
$CaO + 3C \xrightarrow{2273 \ K} CaC_2 + CO$
$Ca + H_2 \rightarrow CaH_2$
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