Ammonia is not produced in the reaction of

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(C) . The products formed in each reaction given in the options are as follows: $(i) \ NH_4Cl + KOH \longrightarrow KCl + NH_3 + H_2O$ $(ii) \ AlN + 3

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$NH_4Cl$ with $NaNO_2$

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(C) . The products formed in each reaction given in the options are as follows: $(i) \ NH_4Cl + KOH \longrightarrow KCl + NH_3 + H_2O$ $(ii) \ AlN + 3H_2O \longrightarrow Al(OH)_3 + NH_3$ $(iii) \ NH_4Cl + NaNO_2 \longrightarrow NaCl + N_2 + 2H_2O$ $(iv) \ 2NH_4Cl + Ca(OH)_2 \longrightarrow CaCl_2 + 2NH_3 + 2H_2O$ Thus,ammonia is not produced in the reaction given in option $(C)$.

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