Ammonia with excess of $Cl_2$ forms:
- A$N_2$
- B$NOCl$
- C$NH_4Cl$
- D$NCl_3$
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Similar Questions
White phosphorus when boiled with a strong solution of caustic soda produces:
Easy
View SolutionWith reference to protonic acids,which of the following statements is correct?
Medium
View SolutionMatch $List-I$ with $List-II$,match the gas evolved during each reaction.
$List-I$ $List-II$ $A$. $(NH_4)_2Cr_2O_7 \xrightarrow{\Delta}$ $I$. $H_2$ $B$. $KMnO_4 + HCl \rightarrow$ $II$. $N_2$ $C$. $Al + NaOH + H_2O \rightarrow$ $III$. $O_2$ $D$. $NaNO_3 \xrightarrow{\Delta}$ $IV$. $Cl_2$
Choose the correct answer from the options given below.
| $List-I$ | $List-II$ |
| $A$. $(NH_4)_2Cr_2O_7 \xrightarrow{\Delta}$ | $I$. $H_2$ |
| $B$. $KMnO_4 + HCl \rightarrow$ | $II$. $N_2$ |
| $C$. $Al + NaOH + H_2O \rightarrow$ | $III$. $O_2$ |
| $D$. $NaNO_3 \xrightarrow{\Delta}$ | $IV$. $Cl_2$ |
Choose the correct answer from the options given below.
In the Ostwald process for the manufacture of $HNO_3$,which of the following is used as a catalyst?
Easy
View SolutionOxidation of $NO$ in air produces
Easy
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