Among KO_2,KAlO_2,CaO_2 and NO_2^+,unpaired e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the presence of an unpaired electron,we analyze the electronic structure of each species:$1$. $KO_2$ (Potassium superoxide): It consi

Vedclass · Accepted Answer

$KO_2$ only

Vedclass · Answer

(C) To determine the presence of an unpaired electron,we analyze the electronic structure of each species:$1$. $KO_2$ (Potassium superoxide): It consists of $K^+$ and $O_2^-$ ions. The superoxide ion $(O_2^-)$ has $17$ valence electrons. According to Molecular Orbital Theory,the configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^2 (\pi^* 2p_y)^1$. It contains one unpaired electron and is paramagnetic.$2$. $KAlO_2$: This is an ionic compound containing $K^+$ and $AlO_2^-$ ions. The $AlO_2^-$ ion has an even number of electrons and all electrons are paired.$3$. $CaO_2$ (Calcium peroxide): It consists of $Ca^{2+}$ and $O_2^{2-}$ (peroxide ion). The peroxide ion has $18$ electrons,all of which are paired.$4$. $NO_2^+$ (Nitronium ion): It has $16$ valence electrons $(5 + 6 	imes 2 - 1 = 16)$. All electrons are paired.Therefore,only $KO_2$ contains an unpaired electron.Hence,option $C$ is correct.

Among $KO_2$,$KAlO_2$,$CaO_2$ and $NO_2^+$,unpaired electron is present in

Similar Questions

Group the following molecules/ions according to their bond order: $O_2^{2-}, Li_2, O_2^{2+}, F_2, N_2, He_2^{2+}$.

Identify the bond order and magnetic nature of $Li_2$ molecule respectively.

Match the following molecules/ions in List-$I$ with their respective bond orders in List-$II$:
| List-$I$ (Molecules/ions) | List-$II$ (Bond order) |
| :--- | :--- |
| $A. N_2^+$ | $I. 1.0$ |
| $B. CO$ | $II. 1.5$ |
| $C. O_2$ | $III. 2.0$ |
| $D. O_2^-$ | $IV. 2.5$ |
| | $V. 3.0$ |

Which of the following species absorbs maximum energy in its $HOMO-LUMO$ electronic transition?

The bond order in $O_2^{2-}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module