Among 15 players,8 are batsmen and 7 are bowl | vedclass

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Question

(A) Total number of ways to select $11$ players from $15$ players is given by ${^{15}C_{11}}$.Number of ways to select $6$ batsmen from $8$ batsmen is

Vedclass · Accepted Answer

$\frac{{^8C_6} 	imes {^7C_5}}{{^{15}C_{11}}}$

Vedclass · Answer

(A) Total number of ways to select $11$ players from $15$ players is given by ${^{15}C_{11}}$.Number of ways to select $6$ batsmen from $8$ batsmen is ${^8C_6}$.Number of ways to select $5$ bowlers from $7$ bowlers is ${^7C_5}$.Therefore,the number of favourable outcomes is ${^8C_6} 	imes {^7C_5}$.The required probability is the ratio of favourable outcomes to total outcomes:$P = \frac{{^8C_6} 	imes {^7C_5}}{{^{15}C_{11}}}$.

Among $15$ players,$8$ are batsmen and $7$ are bowlers. Find the probability that a team is chosen of $6$ batsmen and $5$ bowlers.

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