Among (I)-(IV),the compound that does not und | vedclass

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(D) The correct answer is $(d)$.In free radical polymerisation,the monomer must be capable of forming a stable radical intermediate. Compounds $(I)$ (

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$IV$

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(D) The correct answer is $(d)$.In free radical polymerisation,the monomer must be capable of forming a stable radical intermediate. Compounds $(I)$ (styrene),$(II)$ (acrylonitrile),and $(III)$ (methyl acrylate) contain electron-withdrawing groups attached to the double bond,which stabilize the radical formed during the propagation step through resonance.Compound $(IV)$,methyl vinyl ether $(CH_2=CH-OCH_3)$,has an electron-donating methoxy group. The oxygen atom donates electron density into the double bond,making it electron-rich. This destabilizes the formation of a radical intermediate in a free radical mechanism,as radical polymerization typically requires electron-deficient alkenes to stabilize the radical center.

Among $(I)-(IV)$,the compound that does not undergo polymerisation under radical initiation is:

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