Among SO_2, NF_3, NH_3, XeF_2, ClF_3 and SF_4 | vedclass

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(D) To determine the correct answer,we analyze each molecule for its dipole moment and the number of lone pairs on the central atom:MoleculeHybridisat

Vedclass · Accepted Answer

$sp^3d$

Vedclass · Answer

(D) To determine the correct answer,we analyze each molecule for its dipole moment and the number of lone pairs on the central atom:MoleculeHybridisation,Dipole Moment,Lone Pairs$SO_2$$sp^2$,Non$-zero$,$1$$NF_3$$sp^3$,Non$-zero$,$1$$NH_3$$sp^3$,Non$-zero$,$1$$XeF_2$$sp^3d$,Zero,$3$$ClF_3$$sp^3d$,Non$-zero$,$2$$SF_4$$sp^3d$,Non$-zero$,$1$Comparing the molecules with a non$-zero$ dipole moment,$ClF_3$ has the highest number of lone pairs on the central atom,which is $2$. The hybridization of $ClF_3$ is $sp^3d$.

Among $SO_2, NF_3, NH_3, XeF_2, ClF_3$ and $SF_4$,the hybridization of the molecule with non$-zero$ dipole moment and highest number of lone$-pairs$ of electrons on the central atom is

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