Among P_4,S_8 and N_2,the elements which unde | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Disproportionation reactions are those in which the same element undergoes both oxidation and reduction.Among the given options,$P_4$ and $S_8$ un

Vedclass · Accepted Answer

$P_4, S_8$ only

Vedclass · Answer

(A) Disproportionation reactions are those in which the same element undergoes both oxidation and reduction.Among the given options,$P_4$ and $S_8$ undergo disproportionation in a strong basic medium according to the following reactions:$P_4 + 3 NaOH + 3 H_2 O \longrightarrow PH_3 + 3 NaH_2 PO_2$$S_8 + 12 NaOH \xrightarrow{\Delta} 2 Na_2 S_2 O_3 + 4 Na_2 S + 6 H_2 O$$N_2$ is very stable and almost inert,therefore it does not undergo this reaction.

Among $P_4$,$S_8$ and $N_2$,the elements which undergo disproportionation when heated with $NaOH$ solution are:

Similar Questions

Assign $A, B, C, D$ from the given type of reaction.
$K_2MnO_4 + H^{+} \longrightarrow KMnO_4 + MnO_2 \downarrow$

Statement-$1$ : $I_2 \rightarrow IO_3^- + I^-$; This is a disproportionation reaction.
Statement-$2$ : Oxidation number of $I$ can vary from $-1$ to $+7$.

Assign $A, B, C, D$ from the given type of reaction.
$Na_2C_2O_4 + H_2SO_4 \text{ (conc.)} \longrightarrow Na_2SO_4 + CO + CO_2$

Which ion undergoes disproportionation in an aqueous solution?

Which is the best description of the behaviour of bromine in the reaction given below $H_2O + Br_2 \to HOBr + HBr$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module