Among $15$ players,$8$ are batsmen and $7$ are bowlers. Find the probability that a team of $11$ players is chosen consisting of $6$ batsmen and $5$ bowlers.
- A$\frac{{}^8C_6 \times {}^7C_5}{{}^{15}C_{11}}$
- B$\frac{{}^8C_6 + {}^7C_5}{{}^{15}C_{11}}$
- C$\frac{15}{28}$
- DNone of these
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