Among the following,which is the strongest ox | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The strength of an oxidizing agent is determined by its reduction potential value. $A$ higher positive reduction potential indicates a stronger ox

Vedclass · Accepted Answer

$Mn^{3+}$

Vedclass · Answer

(A) The strength of an oxidizing agent is determined by its reduction potential value. $A$ higher positive reduction potential indicates a stronger oxidizing agent.Comparing the standard reduction potentials $(E^{0})$ for the given ions:$E^{0}_{Mn^{3+}/Mn^{2+}} = +1.51 \, V$$E^{0}_{Fe^{3+}/Fe^{2+}} = +0.77 \, V$$E^{0}_{Ti^{3+}/Ti^{2+}} = -0.37 \, V$$E^{0}_{Cr^{3+}/Cr^{2+}} = -0.41 \, V$Since $Mn^{3+}$ has the highest positive reduction potential,it is the strongest oxidizing agent among the given options.

Among the following,which is the strongest oxidizing agent?

Similar Questions

Identify the correct statement about properties of interstitial compounds.

Which of these statements is not true?

The copper $(II)$ halide which does not exist is:

Which of the following metal hydroxide is not soluble in excess of $NH_3$ solution?

Among $K, Ca, Fe,$ and $Zn$,the element which can form more than one binary compound with chlorine is

Vedclass Test Series

Exam Paper Generator

Online Exam Module