Among the following complexes (K-P),K_3[Fe(CN | vedclass

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(C) $K \Rightarrow K_3[Fe(CN)_6], Fe^{3+} = 3d^5$ (has $5$ unpaired electrons). It is paramagnetic.$L \Rightarrow [Co(NH_3)_6]Cl_3, Co^{3+} = 3d^6$. $

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$L, M, O, P$

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(C) $K \Rightarrow K_3[Fe(CN)_6], Fe^{3+} = 3d^5$ (has $5$ unpaired electrons). It is paramagnetic.$L \Rightarrow [Co(NH_3)_6]Cl_3, Co^{3+} = 3d^6$. $NH_3$ is a strong field ligand,causing pairing. It is diamagnetic.$M \Rightarrow Na_3[Co(ox)_3], Co^{3+} = 3d^6$. Oxalate $(ox^{2-})$ acts as a strong field ligand with $Co^{3+}$,causing pairing. It is diamagnetic.$N \Rightarrow [Ni(H_2O)_6]Cl_2, Ni^{2+} = 3d^8$ (has $2$ unpaired electrons). It is paramagnetic.$O \Rightarrow K_2[Pt(CN)_4], Pt^{2+} = 5d^8$. $CN^{-}$ is a strong field ligand and $5d$ orbitals have large splitting. It is diamagnetic.$P \Rightarrow [Zn(H_2O)_6](NO_3)_2, Zn^{2+} = 3d^{10}$. All electrons are paired. It is diamagnetic.Therefore,the diamagnetic complexes are $L, M, O, P$.

Among the following complexes $(K-P)$,
$K_3[Fe(CN)_6]$ $(K)$,$[Co(NH_3)_6]Cl_3$ $(L)$,$Na_3[Co(ox)_3]$ $(M)$,$[Ni(H_2O)_6]Cl_2$ $(N)$,$K_2[Pt(CN)_4]$ $(O)$ and $[Zn(H_2O)_6](NO_3)_2$ $(P)$,the diamagnetic complexes are

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Among the following complexes $(K-P)$,$K_3[Fe(CN)_6]$ $(K)$,$[Co(NH_3)_6]Cl_3$ $(L)$,$Na_3[Co(ox)_3]$ $(M)$,$[Ni(H_2O)_6]Cl_2$ $(N)$,$K_2[Pt(CN)_4]$ $(O)$ and $[Zn(H_2O)_6](NO_3)_2$ $(P)$,the diamagnetic complexes are