Among the following compounds,the most basic | vedclass

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(D) To determine the basicity,we look at the availability of the lone pair of electrons on the nitrogen or oxygen atom.$A$. Pyridine: The lone pair on

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Pyrrolidine

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(D) To determine the basicity,we look at the availability of the lone pair of electrons on the nitrogen or oxygen atom.$A$. Pyridine: The lone pair on $N$ is in an $sp^2$ orbital and is not involved in the aromatic sextet. It is available for protonation,making it a weak base.$B$. Pyrrole: The lone pair on $N$ is involved in the aromatic sextet (it is part of the $6\pi$ electron system). Thus,it is not available for protonation,making it extremely weakly basic.$C$. Furan: The lone pair on $O$ is involved in the aromatic sextet. It is not available for protonation.$D$. Pyrrolidine: This is a saturated cyclic amine. The lone pair on $N$ is in an $sp^3$ orbital and is not involved in any resonance or aromatic system. It is highly available for protonation,making it the most basic compound among the given options.Therefore,the correct order of basicity is: $	ext{Pyrrolidine} > 	ext{Pyridine} > 	ext{Pyrrole} > 	ext{Furan}$.

Among the following compounds,the most basic compound is

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