Among the following free radical bromination | vedclass

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(B) Bromination is highly selective for the most stable radical intermediate.$(P)$ Cyclohexane gives bromocyclohexane ($2^o$ halide).$(Q)$ Methylcyclo

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$P, R, U$

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(B) Bromination is highly selective for the most stable radical intermediate.$(P)$ Cyclohexane gives bromocyclohexane ($2^o$ halide).$(Q)$ Methylcyclobutane gives $1-$bromo$-1-$methylcyclobutane ($3^o$ halide).$(R)$ Ethylbenzene gives $1-$bromo$-1-$phenylethane (benzylic halide,which is more stable than $2^o$ alkyl halide,but often classified as $2^o$ in terms of carbon substitution).$(S)$ $3-$Methylhexane gives $3-$bromo$-3-$methylhexane ($3^o$ halide).$(T)$ Decalin gives a $3^o$ halide at the bridgehead position.$(U)$ Butane gives $2-$bromobutane ($2^o$ halide).Therefore,$P, R, U$ are the reactions where $2^o$ (or equivalent) halides are the major products.

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