Among the following species N_{2},N_{2}^{+},N | vedclass

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(C) To determine diamagnetism,we check the number of electrons in each species:$N_{2}$ ($14$ $e^-$): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^

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$2$

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(C) To determine diamagnetism,we check the number of electrons in each species:$N_{2}$ ($14$ $e^-$): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$ (All paired,Diamagnetic)$N_{2}^{+}$ ($13$ $e^-$): Paramagnetic$N_{2}^{-}$ ($15$ $e^-$): Paramagnetic$N_{2}^{2-}$ ($16$ $e^-$): Paramagnetic$O_{2}$ ($16$ $e^-$): Paramagnetic$O_{2}^{+}$ ($15$ $e^-$): Paramagnetic$O_{2}^{-}$ ($17$ $e^-$): Paramagnetic$O_{2}^{2-}$ ($18$ $e^-$): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$ (All paired,Diamagnetic)Thus,the species showing diamagnetism are $N_{2}$ and $O_{2}^{2-}$.The total number of diamagnetic species is $2$.

Among the following species $N_{2}$,$N_{2}^{+}$,$N_{2}^{-}$,$N_{2}^{2-}$,$O_{2}$,$O_{2}^{+}$,$O_{2}^{-}$,$O_{2}^{2-}$,the number of species showing diamagnetism is:

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