Among the following,the species that is both | vedclass

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(C) The correct option is $C$.In $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. Thus,its electronic configuration is $3d^8 4s^2$.In the ground state,$

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$Ni(CO)_4$

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(C) The correct option is $C$.In $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. Thus,its electronic configuration is $3d^8 4s^2$.In the ground state,$Ni$ has two unpaired electrons in the $3d$ orbital.$CO$ is a strong field ligand,which causes the pairing of electrons. The two $4s$ electrons are promoted to the $3d$ orbital,resulting in a $3d^{10} 4s^0$ configuration.Since $Ni(CO)_4$ undergoes $sp^3$ hybridization,its geometry is tetrahedral.Furthermore,all electrons are paired,making it diamagnetic in nature.

Among the following,the species that is both tetrahedral and diamagnetic is:

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