Amongst the given elements,which one exhibits | vedclass

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(A) The lanthanoids exhibit a common oxidation state of $+3$. However,$Ce$ (Cerium,$Z=58$) has an electronic configuration of $[Xe] 4f^1 5d^1 6s^2$. U

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$Ce$

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(A) The lanthanoids exhibit a common oxidation state of $+3$. However,$Ce$ (Cerium,$Z=58$) has an electronic configuration of $[Xe] 4f^1 5d^1 6s^2$. Upon losing four electrons,it attains the stable noble gas configuration of $Xe$. Thus,$Ce^{4+}$ is a stable ion in an aqueous medium,making it a strong oxidizing agent. Other elements like $Eu^{2+}$ and $Yb^{2+}$ are stable,while $Tl$ is a post-transition metal that typically shows $+1$ and $+3$ oxidation states.

List-$I$ (Property)	List-$II$ (Element)
$(A)$ Lanthanoid showing $+4$ oxidation state	$(i)$ $Pm$
$(B)$ Lanthanoid showing $+2$ oxidation state	$(ii)$ $Ce$
$(C)$ Radioactive lanthanoid	$(iii)$ $Lu$
$(D)$ Lanthanoid with $4f^7$ configuration in $+3$ state	$(iv)$ $Eu$
$(E)$ Lanthanoid with $4f^{14}$ configuration in $+3$ state	$(v)$ $Gd$
-	$(vi)$ $Dy$

Amongst the given elements,which one exhibits a $+4$ oxidation state in an aqueous medium?

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