Amongst the following,which one will have max | vedclass

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(C) To determine the maximum 'lone pair - lone pair' (lp-lp) repulsions,we analyze the number of lone pairs on the central atom for each molecule:$1$.

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$XeF_{2}$

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(C) To determine the maximum 'lone pair - lone pair' (lp-lp) repulsions,we analyze the number of lone pairs on the central atom for each molecule:$1$. $IF_{5}$: Iodine has $7$ valence electrons. It forms $5$ bonds with $F$ atoms,leaving $1$ lone pair. Number of lp-lp repulsions = $0$.$2$. $SF_{4}$: Sulfur has $6$ valence electrons. It forms $4$ bonds with $F$ atoms,leaving $1$ lone pair. Number of lp-lp repulsions = $0$.$3$. $XeF_{2}$: Xenon has $8$ valence electrons. It forms $2$ bonds with $F$ atoms,leaving $3$ lone pairs. These $3$ lone pairs occupy the equatorial positions of the trigonal bipyramidal geometry,resulting in $3$ lp-lp repulsions at $90^\circ$ angles.$4$. $ClF_{3}$: Chlorine has $7$ valence electrons. It forms $3$ bonds with $F$ atoms,leaving $2$ lone pairs. Number of lp-lp repulsions = $1$.Comparing these,$XeF_{2}$ has the maximum number of lone pair - lone pair repulsions.

Amongst the following,which one will have maximum 'lone pair - lone pair' electron repulsions?

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