An fcc unit cell of aluminium contains the eq | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In an $fcc$ (face-centered cubic) unit cell:$1.$ Atoms at the corners: There are $8$ corners,and each corner atom contributes $\frac{1}{8}$ to the

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) In an $fcc$ (face-centered cubic) unit cell:$1.$ Atoms at the corners: There are $8$ corners,and each corner atom contributes $\frac{1}{8}$ to the unit cell. So,$\frac{1}{8} 	imes 8 = 1$ atom.$2.$ Atoms at the face centers: There are $6$ faces,and each face-centered atom contributes $\frac{1}{2}$ to the unit cell. So,$\frac{1}{2} 	imes 6 = 3$ atoms.$3.$ Total number of atoms $(Z)$ = $1 + 3 = 4$ atoms.

An $fcc$ unit cell of aluminium contains the equivalent of how many atoms?

Similar Questions

$KBr$ crystallizes in a $fcc$ lattice (similar to $NaCl$). The second nearest neighbor of $K^+$ ion and its number are:

What is the coordination number of $Cu$ in a face-centered cubic $(fcc)$ lattice?

In an $fcc$ crystal lattice,atoms $A$ are present at the corners and atoms $B$ are present at the face centers. If one atom $A$ is missing from a corner,what is the molecular formula of the compound?

Structure similar to zinc blende is found in

What is the minimum value of the radius ratio ${r_ + }/{r_ - }$ for $NaCl$ to ensure that anion-anion contact does not occur?

Vedclass Test Series

Exam Paper Generator

Online Exam Module