An alpha-particle (mass 4 text{ amu}) and a s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The radius of a charged particle moving in a magnetic field is given by $r = \frac{mv}{qB} = \frac{\sqrt{2mK}}{qB}$.Since the particle is accelera

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The radius of a charged particle moving in a magnetic field is given by $r = \frac{mv}{qB} = \frac{\sqrt{2mK}}{qB}$.Since the particle is accelerated through a potential $V$,the kinetic energy $K = qV$.Substituting this,we get $r = \frac{\sqrt{2mqV}}{qB} = \frac{1}{B} \sqrt{\frac{2mV}{q}}$.For the $\alpha$-particle: $m_\alpha = 4 	ext{ amu}$,$q_\alpha = 2e$.For the sulfur ion: $m_s = 32 	ext{ amu}$,$q_s = 1e$.The ratio of the radii is $\frac{r_s}{r_\alpha} = \frac{\sqrt{m_s/q_s}}{\sqrt{m_\alpha/q_\alpha}} = \sqrt{\frac{m_s}{m_\alpha} \cdot \frac{q_\alpha}{q_s}}$.Substituting the values: $\frac{r_s}{r_\alpha} = \sqrt{\frac{32}{4} \cdot \frac{2}{1}} = \sqrt{8 \cdot 2} = \sqrt{16} = 4$.

Similar Questions

An electron falling freely under the influence of gravity enters a uniform magnetic field directed towards the south. The electron is initially deflected towards:

An electron,a proton,a deuteron,and an $\alpha -$ particle enter a uniform magnetic field normally with the same velocity. Which particle will have the maximum rotational frequency?

$A$ particle of charge $q$ and mass $m$ starts moving from the origin under the action of an electric field $\vec{E} = E_0 \hat{i}$ and a magnetic field $\vec{B} = B_0 \hat{i}$ with an initial velocity $\vec{v} = v_0 \hat{j}$. The speed of the particle will become $2v_0$ after a time:

Vedclass Test Series

Exam Paper Generator

Online Exam Module