An alcohol X (C_4H_{10}O) does not give turbi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Lucas test uses conc. $HCl$ and $ZnCl_2$ to distinguish between $1^{\circ}$,$2^{\circ}$,and $3^{\circ}$ alcohols. $3^{\circ}$ alcohols give im

Vedclass · Accepted Answer

$n$-butanol,$PCC$,butanal

Vedclass · Answer

(A) The Lucas test uses conc. $HCl$ and $ZnCl_2$ to distinguish between $1^{\circ}$,$2^{\circ}$,and $3^{\circ}$ alcohols. $3^{\circ}$ alcohols give immediate turbidity,$2^{\circ}$ alcohols give turbidity within $5-10$ minutes,and $1^{\circ}$ alcohols do not give turbidity at room temperature. Since alcohol $X$ $(C_4H_{10}O)$ does not give turbidity at room temperature,it must be a $1^{\circ}$ alcohol. Among the options,$n$-butanol is a $1^{\circ}$ alcohol. $n$-butanol reacts with $PCC$ (Pyridinium chlorochromate) to form butanal $(Z)$. Therefore,$X = n$-butanol,$Y = PCC$,and $Z = 	ext{butanal}$.

An alcohol $X$ $(C_4H_{10}O)$ does not give turbidity with conc. $HCl$ and $ZnCl_2$ at room temperature. $X$ on reaction with reagent $Y$ gives $Z$. What are $X, Y$ and $Z$ respectively?

Similar Questions

Write the mechanism of the acid dehydration of ethanol to yield ethene.

The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with

The boiling point of an alcohol is comparatively higher than that of the corresponding alkane due to:

Tertiary alcohols $(3^{\circ})$ having at least four carbon atoms upon drastic oxidation yield carboxylic acid with:

$HO-CH_2CH_2CH_2CH_2-Br \xrightarrow{KOH} \text{Product}$. The product is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module