An alkane forms isomers if the number of carb | vedclass

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(D) Structural isomerism in alkanes requires a minimum of $4$ carbon atoms to form branched structures. For $n=1$ (methane),$n=2$ (ethane),and $n=3$ (

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) Structural isomerism in alkanes requires a minimum of $4$ carbon atoms to form branched structures. For $n=1$ (methane),$n=2$ (ethane),and $n=3$ (propane),only one structural arrangement is possible. For $n=4$ (butane),two isomers exist: $n$-butane $(CH_3-CH_2-CH_2-CH_3)$ and isobutane $(CH_3-CH(CH_3)-CH_3)$. Therefore,the correct answer is $4$.

An alkane forms isomers if the number of carbon atoms is at least

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