An alkene $X$ with formula $C_4H_8$ does not exhibit geometrical isomerism. In the conversion of $X$ to $Y$,the correct sequence of reagents $A$ and $B$ used are ($Y$ gives iodoform test):
$X$ $\xrightarrow{A} \text{Intermediate}$ $\xrightarrow{B} Y$

Ethylene reacts with ..... to form ethylene chlorohydrin.

With oxalic acid,glycerol at $260\,^\circ C$ gives

The stability order of the given alkenes is

$but-2-yne$ is reacted separately with one mole of $H_2$ as shown below:
$\underline{ B } \xleftarrow[\text{liq } NH_3]{Na} CH_3-C \equiv C-CH_3 \xrightarrow[\Delta]{Pd/C} \underline{ A }$
Identify the incorrect statements from the options given below:
$A.$ $A$ is more soluble than $B$.
$B.$ The boiling point and melting point of $A$ are higher and lower than $B$ respectively.
$C.$ $A$ is more polar than $B$ because dipole moment of $A$ is zero.
$D.$ $Br_2$ adds easily to $B$ than $A$.

The reaction of $3$-phenylpropene with $HBr$ gives (as the major product):