An alkyne has the molecular formula C_6H_{10} | vedclass

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(D) The general formula for an alkyne is $C_nH_{2n-2}$. For $C_6H_{10}$,$n=6$. $1$-alkynes have the triple bond at the terminal position,represented a

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$4$

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(D) The general formula for an alkyne is $C_nH_{2n-2}$. For $C_6H_{10}$,$n=6$. $1$-alkynes have the triple bond at the terminal position,represented as $R-C \equiv CH$. For a $6$-carbon chain,the possible structures for $1$-alkynes are: $1$. $CH_3-CH_2-CH_2-CH_2-C \equiv CH$ $(hex-1-yne)$ $2$. $CH_3-CH_2-CH(CH_3)-C \equiv CH$ $(3-methylpent-1-yne)$ $3$. $CH_3-CH(CH_3)-CH_2-C \equiv CH$ $(4-methylpent-1-yne)$ $4$. $(CH_3)_3C-C \equiv CH$ $(3,3-dimethylbut-1-yne)$ Thus,there are $4$ possible isomers for $1$-alkyne.

An alkyne has the molecular formula $C_6H_{10}$. The number of $1$-alkyne isomers (excluding stereoisomers) possible for it is

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