An alternating current is given by $I = I_A \sin \omega t + I_B \cos \omega t$. The r.m.s. current will be

$A$ resistance of $20 \, \Omega$ is connected to a source of an alternating potential $V = 220 \sin(100 \pi t)$. The time taken by the current to change from its peak value to its r.m.s. value is:

At time $t=0 \text{ s}$, the voltage of an $AC$ generator starts from $0 \text{ V}$ and becomes $2 \text{ V}$ at time $t=\frac{1}{100 \pi} \text{ s}$. The voltage increases up to $100 \text{ V}$, after which it starts to decrease. Find the frequency of the generator. (in $\text{ Hz}$)

The $ rms $ value of current in a $ 50 \,Hz $ $ AC $ circuit is $ 6 \,A $. The average value of $ AC $ current over a complete cycle is:

An alternating e.m.f. is given by $e = e_0 \sin \omega t$. In what time will the e.m.f. reach half its maximum value, if $e$ starts from zero? (Given: $\sin 30^{\circ} = 0.5$)

The average value of alternating current $I = I_0 \sin \omega t$ in the time interval $[0, \frac{\pi}{\omega}]$ is: