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(D) The instantaneous current in the primary coil is given by $I = I_0 \sin(\omega t)$.Given peak current $I_0 = \frac{2}{\pi} 	ext{ A}$ and frequenc

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$200$

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(D) The instantaneous current in the primary coil is given by $I = I_0 \sin(\omega t)$.Given peak current $I_0 = \frac{2}{\pi} 	ext{ A}$ and frequency $v = 50 	ext{ Hz}$.The angular frequency is $\omega = 2 \pi v = 2 \pi(50) = 100 \pi 	ext{ rad/s}$.The rate of change of current is $\frac{dI}{dt} = I_0 \omega \cos(\omega t)$.The maximum value of the rate of change of current is $\left(\frac{dI}{dt}ight)_{	ext{max}} = I_0 \omega$.Substituting the values: $\left(\frac{dI}{dt}ight)_{	ext{max}} = \left(\frac{2}{\pi}ight) 	imes (100 \pi) = 200 	ext{ A/s}$.The induced e.m.f. in the secondary coil is $E = M \left|\frac{dI}{dt}ight|$,where $M = 1 	ext{ H}$.Therefore,the peak induced e.m.f. is $E_0 = 1 	imes 200 = 200 	ext{ V}$.

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