An ammeter reads up to $1\, A$. Its internal resistance is $0.81\, \Omega$. To increase the range to $10\, A$,the value of the required shunt is ............ $\Omega$.

$A$ galvanometer of resistance $G$ has a voltage range $V_g$. The resistance required to convert it to read voltage up to $V$ is

When a shunt of $4\,\Omega$ is connected to a galvanometer,the deflection reduces to $1/5$ of its initial value. If an additional shunt of $2\,\Omega$ is connected in parallel,what will be the new deflection?

We have a galvanometer of resistance $25\,\Omega$. It is shunted by a $2.5\,\Omega$ wire. The part of the total current that flows through the galvanometer is given as:

$A$ galvanometer can be converted into an ammeter by connecting:

Write the equation for the maximum torque acting on a current-carrying loop in a galvanometer.