An angular impulse of $20 \,Nms$ is applied to a hollow cylinder of mass $2 \,kg$ and radius $20 \,cm$. The change in its angular speed is ............. $rad/s$.

Derive the equation of angular momentum in the case of rotational motion about a fixed axis.

$A$ particle of mass $2\, kg$ is on a smooth horizontal table and moves in a circular path of radius $0.6\, m$. The height of the table from the ground is $0.8\, m$. If the angular speed of the particle is $12\, rad\, s^{-1}$,the magnitude of its angular momentum about a point on the ground right under the centre of the circle is ........ $kg\, m^2\, s^{-1}$.

$A$ particle is moving in a circular path of radius $a$ with a constant speed $v$ as shown in the figure. The centre of the circle is marked by $C$. The angular momentum about the origin $O$ can be written as:

The angular momentum of a system of particles changes if:

$A$ particle of mass $m$ moves with a velocity $v$ along the line $PC$ as shown in the figure. What is the angular momentum of the particle about $O$?