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(C) Sodium carbonate $(Na_2CO_3)$ is a salt formed from the neutralization of a strong base,sodium hydroxide $(NaOH)$,and a weak acid,carbonic acid $(

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Weak acid and strong base

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(C) Sodium carbonate $(Na_2CO_3)$ is a salt formed from the neutralization of a strong base,sodium hydroxide $(NaOH)$,and a weak acid,carbonic acid $(H_2CO_3)$.When dissolved in water,it undergoes hydrolysis:$Na_2CO_3 + 2H_2O ⇌ 2NaOH + H_2CO_3$.Since $NaOH$ is a strong base and $H_2CO_3$ is a weak acid,the resulting solution contains an excess of $OH^-$ ions,making the solution alkaline (basic).

Column $I$	Column $II$
$A$. $CH_3COONa$	$i$. Almost neutral,$pH > 7$ or $< 7$
$B$. $NH_4Cl$	$ii$. Acidic,$pH < 7$
$C$. $NaNO_3$	$iii$. Alkaline,$pH > 7$
$D$. $CH_3COONH_4$	$iv$. Neutral,$pH = 7$

An aqueous solution of sodium carbonate is alkaline because sodium carbonate is a salt of

Similar Questions

Match the column $I$ with column $II$ and mark the appropriate choice.

Column $I$ Column $II$

$A$. $CH_3COONa$ $i$. Almost neutral,$pH > 7$ or $< 7$

$B$. $NH_4Cl$ $ii$. Acidic,$pH < 7$

$C$. $NaNO_3$ $iii$. Alkaline,$pH > 7$

$D$. $CH_3COONH_4$ $iv$. Neutral,$pH = 7$

Which of the following substances undergoes hydrolysis?

Hydrolysis of sodium acetate will give:

Which of the following compounds give a basic solution on hydrolysis?
$(1)$ $NH_4Cl$
$(2)$ $K_2CO_3$
$(3)$ $Na_2B_4O_7 \cdot 10 H_2O$
$(4)$ $NaCl$

Calculate the $pH$ of a $0.5 \ M$ aqueous solution of $KCN$. Given that $pK_{b}$ for $CN^{-} = 4.70$. (in $.5$)

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