An aqueous solution of sodium nitrite on boil | vedclass

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Question

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorin

Vedclass · Accepted Answer

Nitroethane

Vedclass · Answer

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorine atom by the nitrite group,followed by decarboxylation upon boiling. The reaction proceeds as follows: $CH_3CHClCOONa + NaNO_2 \rightarrow CH_3CH(NO_2)COONa + NaCl$ Upon boiling,the intermediate undergoes decarboxylation: $CH_3CH(NO_2)COONa \xrightarrow{\Delta} CH_3CH_2NO_2 + CO_2 + NaCl$ Thus,the final product is nitroethane.

An aqueous solution of sodium nitrite on boiling with $\alpha$-chlorosodium propionate gives:

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