An aromatic compound $A$ of formula $C_7H_6Cl_2$ gives $AgCl$ on boiling with alcoholic $AgNO_3$ solution,and yields $C_7H_7OCl$ on treatment with sodium hydroxide. $A$ on oxidation gives a monochlorobenzoic acid which affords only one mononitro derivative. The compound $A$ is :
- A$p-$chlorobenzyl chloride
- B$o-$chlorobenzyl chloride
- C$m-$chlorobenzyl chloride
- Dbenzyl chloride
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Similar Questions
The number of possible isomeric products formed when $3$-chloro-$1$-butene reacts with $HCl$ through carbocation formation is $.............$.
Consider the following $E_1/S_N1$ reaction. The missing product$(s)$ is(are):
Difficult
View SolutionWhich of the following is $NOT$ obtained when a mixture of chloroethane and $1-$chloropropane is treated with sodium metal in dry ether?
Assertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.
Reason : Alkyl halides are less reactive than acyl halides.
Match the reactions in Column-$I$ with their mechanisms in Column-$II$.
Column-$I$ (Reaction) Column-$II$ (Mechanism) $(A)$ $OH^- + CH_3Cl \to HOCH_3 + Cl^-$ $(1)$ $S_N2$ mechanism $(B)$ $(CH_3)_3CBr + OH^- \to (CH_3)_3COH + Br^-$ $(2)$ $S_E2$ aromatic $(C)$ $CH_3CH_2Br \xrightarrow[ethanol]{KOH} CH_2 = CH_2$ $(3)$ $S_N1$ mechanism $(D)$ $C_6H_6 + Br_2 \xrightarrow{Fe} C_6H_5Br + HBr$ $(4)$ $\beta$-elimination (dehydrohalogenation)
| Column-$I$ (Reaction) | Column-$II$ (Mechanism) |
| $(A)$ $OH^- + CH_3Cl \to HOCH_3 + Cl^-$ | $(1)$ $S_N2$ mechanism |
| $(B)$ $(CH_3)_3CBr + OH^- \to (CH_3)_3COH + Br^-$ | $(2)$ $S_E2$ aromatic |
| $(C)$ $CH_3CH_2Br \xrightarrow[ethanol]{KOH} CH_2 = CH_2$ | $(3)$ $S_N1$ mechanism |
| $(D)$ $C_6H_6 + Br_2 \xrightarrow{Fe} C_6H_5Br + HBr$ | $(4)$ $\beta$-elimination (dehydrohalogenation) |
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