An astronomical refracting telescope has an o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Focal length of objective $f_o = 20 \, m = 2000 \, cm$,Focal length of eyepiece $f_e = 2 \, cm$.$1$. Magnification $(m)$: For a telescope i

Vedclass · Accepted Answer

All of these

Vedclass · Answer

(D) Given: Focal length of objective $f_o = 20 \, m = 2000 \, cm$,Focal length of eyepiece $f_e = 2 \, cm$.$1$. Magnification $(m)$: For a telescope in normal adjustment,$m = \frac{f_o}{f_e} = \frac{2000 \, cm}{2 \, cm} = 1000$.$2$. Tube length $(L)$: For normal adjustment,$L = f_o + f_e = 20 \, m + 0.02 \, m = 20.02 \, m$.$3$. Nature of image: An astronomical telescope forms an inverted image with respect to the object.Since all statements are correct,the correct option is $D$.

An astronomical refracting telescope has an objective of focal length $20 \, m$ and an eyepiece of focal length $2 \, cm$. Then:

Similar Questions

$A$ lens of large focal length and large aperture is best suited as an objective of an astronomical telescope since :

The magnifying power of a telescope can be increased by

The angular magnification of an astronomical telescope is $10$. The final image is formed at infinity. The length of the telescope is $44 \, cm$. The focal length of the objective lens is .......... $cm$.

The focal lengths of the lenses of an astronomical telescope are $50\, cm$ and $5\, cm$. The length of the telescope when the image is formed at the least distance of distinct vision is

An opera glass (Galilean telescope) measures $9 \, cm$ from the objective to the eyepiece. The focal length of the objective is $15 \, cm$. Its magnifying power is

Vedclass Test Series

Exam Paper Generator

Online Exam Module