An athlete completes one round of a circular | vedclass

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(A) Diameter of circular track $(D) = 200\, m$.Radius of circular track $(r) = D / 2 = 100\, m$.Time taken for one round $(t) = 40\, s$.Total time giv

Vedclass · Accepted Answer

$Distance\, covered=2200\,m;\, Displacement=200\,m$

Vedclass · Answer

(A) Diameter of circular track $(D) = 200\, m$.Radius of circular track $(r) = D / 2 = 100\, m$.Time taken for one round $(t) = 40\, s$.Total time given $= 2\, min\, 20\, s = 140\, s$.Number of rounds $= 140 / 40 = 3.5\, rounds$.Distance covered $= 3.5 	imes (2 \pi r) = 3.5 	imes 2 	imes (22/7) 	imes 100 = 7 	imes (22/7) 	imes 100 = 2200\, m$.After $3.5\, rounds$, the athlete will be at the diametrically opposite point of the starting position.Displacement $= 	ext{Diameter of the circular track} = 200\, m$.

An athlete completes one round of a circular track of diameter $200\, m$ in $40\, s$. What will be the distance covered and the displacement at the end of $2\, min$ $20\, s$?

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