An athlete completes one round of a circular | vedclass

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(B) The total time given is $2 \,min \,20 \,s$.Converting this into seconds: $2 	imes 60 \,s + 20 \,s = 120 \,s + 20 \,s = 140 \,s$.The athlete compl

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$2 R$

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(B) The total time given is $2 \,min \,20 \,s$.Converting this into seconds: $2 	imes 60 \,s + 20 \,s = 120 \,s + 20 \,s = 140 \,s$.The athlete completes one round in $40 \,s$.The number of rounds completed in $140 \,s$ is $\frac{140}{40} = 3.5$ rounds.After $3$ complete rounds, the athlete returns to the starting point, so the displacement for these $3$ rounds is $0$.In the remaining $0.5$ round, the athlete moves from the starting point $A$ to the diametrically opposite point $B$.The displacement is the shortest distance between the initial and final positions, which is the diameter of the circular track.Therefore, the displacement $= 2R$.

An athlete completes one round of a circular track of radius $R$ in $40 \,s$. What will be his displacement at the end of $2 \,min \,20 \,s$?

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