An athlete in the Olympic games covers a dist | vedclass

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(A) The average speed of the athlete is $v = \frac{100 \ m}{10 \ s} = 10 \ m/s$.The kinetic energy $(K.E.)$ is given by the formula $K.E. = \frac{1}{2

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$2000 \ J - 5000 \ J$

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(A) The average speed of the athlete is $v = \frac{100 \ m}{10 \ s} = 10 \ m/s$.The kinetic energy $(K.E.)$ is given by the formula $K.E. = \frac{1}{2}mv^2$.Assuming the mass $(m)$ of an athlete typically ranges between $40 \ kg$ and $100 \ kg$:For $m = 40 \ kg$: $K.E. = \frac{1}{2} 	imes 40 	imes (10)^2 = 20 	imes 100 = 2000 \ J$.For $m = 100 \ kg$: $K.E. = \frac{1}{2} 	imes 100 	imes (10)^2 = 50 	imes 100 = 5000 \ J$.Thus,the range of kinetic energy is $2000 \ J - 5000 \ J$.

An athlete in the Olympic games covers a distance of $100 \ m$ in $10 \ s$. His kinetic energy can be estimated to be in the range

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