An athlete is given 100 g of glucose (C_6H_{ | vedclass

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(B) Total energy provided by $100 \ g$ of glucose is $1800 \ kJ$.Energy utilized for sports activities is $50 \%$ of $1800 \ kJ = 900 \ kJ$.The remain

Vedclass · Accepted Answer

$360$

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(B) Total energy provided by $100 \ g$ of glucose is $1800 \ kJ$.Energy utilized for sports activities is $50 \%$ of $1800 \ kJ = 900 \ kJ$.The remaining $900 \ kJ$ of energy must be dissipated to avoid storage,which is done through the evaporation of water.Enthalpy of evaporation of water is $\Delta H_{vap} = 45 \ kJ \ mol^{-1}$.Number of moles of water required to dissipate $900 \ kJ$ is $n = \frac{900 \ kJ}{45 \ kJ \ mol^{-1}} = 20 \ mol$.Molar mass of water $(H_2O)$ is $(2 	imes 1) + 16 = 18 \ g \ mol^{-1}$.Mass of water to be perspired $= n 	imes M = 20 \ mol 	imes 18 \ g \ mol^{-1} = 360 \ g$.

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